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20x^2-157x+78=0
a = 20; b = -157; c = +78;
Δ = b2-4ac
Δ = -1572-4·20·78
Δ = 18409
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-157)-\sqrt{18409}}{2*20}=\frac{157-\sqrt{18409}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-157)+\sqrt{18409}}{2*20}=\frac{157+\sqrt{18409}}{40} $
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